huangminz

compare the results of the single run to the 2,500 runs.For the two results, compute the sum of squared residuals given by

$\text{SSR} = \sum_{g = 1}^G \sum_{i: \mathbf{x}_i \in C_g}d(\mathbf{x}_i,\bar{\mathbf{c}}_g)^2$
where $G$ is the number of groups, $C_g$ is the set of points in cluster $g$, and $d(\mathbf{x}_i,\bar{\mathbf{c}}_g)$ is the Euclidean distance between $\mathbf{x}_i$ and the mean of its cluster $\bar{\mathbf{c}}_g$.

对于single run 而言是 算出每组的 Euclidean distance 的平方然后根据组内有多少da ta
data相加 ， 但是如何算2500组的SSR呢